**Maths Puzzle - 19 December**

How can I get the answer 24 by only using the numbers 8,8,3,3.

You can use the main signs add, subtract multiply and divide.

**For Solution :**Click Here

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How can I get the answer 24 by only using the numbers 8,8,3,3.

You can use the main signs add, subtract multiply and divide.

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8*8/3 + 3

ReplyDeleteThe Answer comes in point (24.333...)!!

Deleteno 64/6 isn't 24

Delete8x8/3+3 is the answer easy

Delete8 x 3 = 24. The question doesn't say you must use all four numbers. Occam's Razor.

Delete(8-3) / ((1/3) - (1/8)) = 24

Delete8+8=16

Delete3+3=6

16+6=24

Bro 16+6 is 22 not 24

DeleteThis comment has been removed by the author.

Delete8.3 =24 then dived by 3 ....then multiply by 3

Delete[(8*8)/(3)]+3

Delete[64/3]+3

21.33+3

=24.33 or 24(round off to whole number)

Steps-->

ReplyDelete1.8/8=1

2.1+3=4

3.4*3!

4*6(since 3 factorial=6)

4.{[(8/8)+3]*3!}=24.☺

Steps-->

ReplyDelete[(8/8)+3]*3!=24

since 3!=6☺

can't use factorial

DeleteCORRECT

DeleteITS unacceptable

8*8/3 + 3

ReplyDelete8/(3-(8/3))

ReplyDeletesuperb...

Deleteawesome :)

Deletesuperb...

Deletesuperb...

Delete24=8/(3-(8/3))=8/(1/3)=8*3=24

ReplyDeleteRoot 8*8*3*3 = 8*3 = 24

ReplyDeleteawesome

Deleteyou can't use root.

Delete8*8/3 + 3 =24

ReplyDeletehaaaaaaaa good

Delete8*3

ReplyDelete8*3

ReplyDeleteu have to use all the given no.s

Delete8/(3-(8/3))

Delete1. square root of 8 x square root of 8 = 8.

ReplyDelete2. square root of 3 x square root of 3 = 3.

3. 8x3 = 24

i did not say u had to use all of them os 8x3=24

Delete8*(3*(3*3-8))=24 Ganesh

ReplyDelete8 square

ReplyDelete3 square

by square root cancel square

then multiply

8*3=24

(8*3!)/3+8

ReplyDeletea=8;b=3

ReplyDelete(a+b+ab)-1 gives right answer is 24

sq.root of (8*8)*sq.root of (3*3)

ReplyDelete=8*3=24!what a silly sum!!!

sqrt(8+8) x (3+3) = 4x6 = 24

ReplyDelete{8+{(8-3)}2}-(3)2=24

ReplyDelete8+25_9=24

33-9=24

8*3-(3/8)

ReplyDelete8*3=24/3=8*3=24

ReplyDelete(root(8,3)+root(8,3)!)

ReplyDelete(2+2)! = 4! = 24

I is confused

ReplyDelete3*8+3*8-3*8 is the answer

ReplyDelete8 + 8 + Ɛ3

ReplyDelete= 8+8+8

=24

1. 8+8=16

ReplyDelete2. 8-3=5

3. 3=3

So, (8+8)+(8-3)+3=24

sqrt(8x3) x sqrt(8x3)

ReplyDeletecuberoot(8)*cuberoot(8)*(3+3)=24

ReplyDelete3x3x8/3=24

ReplyDeleteI have a better solution, 8×3=24! Nobody says you have to use all of them.......

ReplyDelete8x3÷8x3

Delete^^^^^ That's 1. duh.

DeleteNo it isn't .... it's 24

DeleteIts so easy. Yous are bringing hard things when you could easily do this. :=: ( ( 8 - 3 ) x 3 ) + 8

ReplyDeleteThat's 23 -_-

Deletesqrt(8^3÷8)*3

ReplyDelete(square route of 8*8)*(square route of 3*3)= 8*3=24

ReplyDelete8*3=8*3

ReplyDelete8+8=16

ReplyDelete16/3

5.33*3=16

16+8=24

3*8-3*8

ReplyDeleteanswer is:

ReplyDelete8/(3-8/3)

1)8/(3-(8/3))

ReplyDelete2)(8-3)!/(8-3)

3)[(8/8)+3]*3!

4)(∛8 × ∛8)!

5)√(8×8×3×3)

6)8+(8×(3!/3))

7)((√(8+8) × (3/3))!

8)√(8+8) × (3+3)

9)(log base(3!/3) of 8) × 8

10)((log base(3!/3) of (8+8))!

30 answers:

ReplyDelete8/(3 - (8/3))

√(8*8*3*3)

(8-3)!/(8-3)

(3!*8/3) + 8

(3!/(³√8))*8

(3!*8) - (3*8)

8 + (3!/(3/8))

((³√8)*(³√8))!

(√(8+8))*(3+3)

(3 + (3*(8-8))!)!

(3!*8)/(8 - (3!))

(3 + ³√((8-8)!))!

((√(8+8))*3/3)!

(√(8*8))*(3!-3)

(3! - 3 + (8/8))!

(3 + (³√(8/8)))!

((³√8) + (³√8))!

(3! - 3 + ((8-8)!))!

(³√8^³√8)!

((8-(3!))*(8-(3!)))!

(((8-(3!))^(8-(3!)))!

38 -8 - (3!)

(8!!*3)/(3!*8)

(8-3)!/(8-3)

8*(3!)/³√8

[8*8/3]+3

(8 + √(8*3/3))!

3!*((8/8)+3)

3!*((8-8)!+3)

3*√((8^3)/8)

8/(3-(8/3))

ReplyDelete