**Easy Maths Riddle - 27 March**

A man had seven children. Upon receiving his salary, he called all of them. He had $100 with him to give to his children. He decided to start with the youngest child and then give $2 more than each younger child to his next elder child.

For example, if he gives $x to the youngest child, he will give $(x+2) to the next one, $[(x+2) + 2] to the next one and so on.

Can you find out how much did the youngest one receive?

**For Solution :**Click Here

He gave about $8,29 to the youngest

ReplyDelete7X + 12 = 100

its18.29 aprox.

ReplyDelete7X+42=100

nice

ReplyDelete$31.33

ReplyDelete8.29$

ReplyDeleteThis comment has been removed by the author.

ReplyDeleteFor younger one he can give $49 and for last elder one he can give $51

ReplyDeleteTotally he can have only two child .

$8.29

ReplyDeletethis problem has an error in it. solution says $16, but if he have all 7 of his children at least 16 bucks thats 112 without adding $2 (n-1)times... sigh

ReplyDelete6 dollar not 16

ReplyDelete