#1 - Hardest Math Riddle

Create a number using only the digits 4,4,3,3,2,2,1 and 1. So i can only be eight digits. You have to make sure the ones are separated by one digit, the twos are separated by two digits the threes are separated with three digits and the fours are separated by four digits

Hardest Math Riddle


#2 - Dollar Cent Maths Riddle

I went to the book shop and spent one half of the money that was in my purse.

When I came out, I found that I had as many cents as I had dollars and half as many dollars as I had cents when I went in. Find the money in my purse when I entered the store.

Dollar Cent Maths Riddle

I have Dollar 99.98 in my purse when I entered the store.

#3 - Simple Simple Google Interview Puzzle

The puzzle is if the shopkeeper can only place the weights in one side of the common balance. For example if shopkeeper has weights 1 and 3 then he can measure 1, 3 and 4 only. Now the question is how many minimum weights and names the weights you will need to measure all weights from 1 to 1000. This is a fairly simple problem and very easy to prove also.  Answer for this puzzle is given below.

Simple Simple Google Interview Puzzle

This is simply the numbers 2^0,2^1,2^2 ... that is 1,2,4,8,16... So for making 1000 kg we need up to 1, 2, 4, 8, 16, 32, 64, 128, and 512

#4 - Distance Problem

Two towns are exactly 100 km apart. Rakesh leaves City A driving at 30 km/hr and Harish leaves City B a half an hour later driving 60 km/hr. Who will be closer to City A when they meet?

Distance Problem

Both would be the same distance from City A.

#5 - Maths Number Puzzle

Can you make four (4) nines (9) equal 100 ?

Maths Number Puzzle

99+9/9 = 100

#6 - rebus picture puzzle for kids

What does this rebus means ?

rebus picture puzzle for kids

Diamond Ring

#7 - Maths Logic Problem

A horse and a camel were carrying boxes on their backs. The horse started complaining to the camel that his load is too heavy.
The camel replied 'Why are you complaining? If you gave me one of your boxes I would have double what you have and if I give you one of my boxes we two would have an even load.'
How many boxes do each of the animal (horse & camel) is carrying ?

Maths Logic Problem

Horse is carrying 5 boxes and the camel is carrying 7 boxes.

Let's assume that the horse was carrying H boxes and the camel was carrying C boxes.
C + 1 = 2 * (X-1)
C + 1 = 2H - 2
C = 2H - 3

C - 1 = H + 1
C = H + 2

2H - 3 = H + 2
H = 5

C = 7

#8 - Mathematical Logic Puzzle

using four eights (8) and a one (1) and one mathematical symbol , create the number 100

Mathematical Logic Puzzle

188 - 88

#9 - February Maths Puzzle

Using eight eights and addition only, can you make 1000?

February Maths Puzzle

888 + 88 + 8 + 8 + 8 = 1000

#10 - Maths Classic Race Puzzle

Lavesh, Bolt, and Lewis race each other in a 100 meters race. All of them run at a constant speed throughout the race.

Lavesh beats Bolt by 20 meters.
Bolt beats Lewis by 20 meters.

How many meters does Lavesh beat Lewis by ?

Maths Classic Race Puzzle

Lavesh beats Lewis by 36 meters.

It is tempting to guess that Lavesh beats Lewis by 40 meters, but when Lavesh finishes and is 20 meters ahead of Bolt, Bolt is NOT 20 meters ahead of Lewis (he's only 16 meters ahead), and it will take a couple more seconds before Bolt increases his lead over Lewis to 20 meters.

To figure out the answer, we let Lavesh's speed be A meter/second. So it takes him 100/A seconds to finish the race. At this point, we know that Bolt has run 80 meters (since Lavesh beats him by 20 meters). So Bolt runs 80 meters in 100/A seconds, meaning that he is running at a speed of (80/(100/A)) meters/second, or (8A/10) meters per second.

So we then know that it takes Bolt 100/(8A/10) seconds to finish the race, or 125/A seconds. At this point, we know that Lewis has run 80 meters (since Bolt beats him by 20 meters). So Lewis runs 80 meters in 125/A seconds, meaning that he is running at a speed of (80/(125/A)) meters/second, or 80A/125 meters per second.

Now that we know Lewis's speed, we just need to figure out how far he had run when Lavesh finished the race. Since Lavesh finished in 100/A seconds, we can determine that Lewis had run (100/A) * (80A/125) = 8000/125 = 64 meters when Lavesh finished the race. And so Lavesh beat him by (100 - 64) = 36 meters.