As you can see in the picture, 20 matchsticks have been used to form five squares. What you have to do is move two of the matchsticks in a manner that seven squares are formed.Please note that you cannot overlap the matches or break them. The squares can be on any size but they must be closed squares.
As you can see in the picture, we have just moved two of the matchsticks and now we have seven squares of 1x1, 2x2 and 3x3 sizes.
All of the flowers I have are orchids except two. All of the flowers I have are hibiscuses except two. All of the flowers I have are roses except two.
Can you tell me how many flowers I have ?
I have two flowers neither of which are orchids, hibiscuses or roses.
Replace the question mark with the correct number.
2 + 2= 4
3 + 3= 18
4 + 4= ?
6 + 6= 180
48
2 + 2= 4 (2*2*1)
3 + 3= 18 (3*3*2)
4 + 4= 48 (4*4*3)
6 + 6= 180 (6*6*5)
Below puzzle is a popular example for rebus puzzles.
Can you tell us what i am thinking by solving the below rebus ?
Feeling on top of the World
here's a cricket riddle for all of cricket lovers
I have played 50 ODI's and my average is 50.
How many runs should i score in my 51st ODI, so that my average score jumps to 51 ?
101
(50 * 50 + x)/51 = 51
=>2500 + x = 51 * 51
=> x = 2601 - 2500
=> x = 101 (Answer)
Can you find the missing figure from the grid? Choose from the options given.
The figure D will fit in the missing position. This is because with every figure, the number of black dots are increasing. Thus the D figure is the only one that I suitable.
You are stuck on an island where you have nothing. You find four pieces of paper somewhere on the island. What will be your strategy to escape from the island safely?
PS: No other resource is available to you on the island, neither can you build anything.
Nothing is the name of a ship that has been docked near the coast. The four pieces of paper contains the map and directions that can be used by you while driving the ship.
A rubber ball keeps on bouncing back to 2/3 of the height from which it is dropped. Can you calculate the fraction of its original height that the ball will bounce after it is dropped and it has bounced four times without any hindrance ?
Let us solve this question one step at a time.
We know that each time the ball is dropped it bounces back and reach 2/3 of the height.
Thus, after the first bounce, the ball will reach 2/3 of the height from which it was dropped.
After the second bounce, the ball will reach 2/3 of the height again after the first bounce.
Thus the total height at which the ball must have reached by this time will be 2/3 * 2/3 = 4/9 of the original height.
After third bounce, 2/3 * 2/3 * 2/3 = 8/27 of the original height.
After fourth bounce, 2/3 * 2/3 * 2/3 * 2/3 = 16/81 of the original height.
Thus, the ball will reach 16/81 of the original height from which it was dropped.
