A quarter is one fourth of a dollar but Mr. Brainteaser has changed the equation as below :
DOLLAR * 4 = QUARTER
Can you replace each letter by a digit to make above solution correct ?
DOLLAR * 4 = QUARTER
457730 * 4 = 1830920
Which number should replace the question mark in the picture below ?
26
14 = 1^2 + 2^2 + 3^2
21 = 4^2 + 1^2 + 2^2
29 = 4^2 + 3^2 + 2^2
26 = 3^2 + 4^2 + 1^2
In "Clash Royal" App Game, Warrior "The Bomber" is a very good defensive options. It can be purchased from the card shop.The cost of the bomber is quite interesting.The Cost of 1st bomber is: 2The Cost of 2nd bomber is: 4The Cost of 3rd bomber is: 6The Cost of 4th bomber is: 8The Cost of 5th bomber is: 10i.e to buy 5 bombers you need 2+4+6+8+10 = 30 coins.How many bombers can you buy using 1000 coins ?
62
The Cost of 1st bomber is: 2 i.e Total coins spend: 2
The Cost of 2nd bomber is: 4 i.e Total coins spend: 6
The Cost of 3rd bomber is: 6 i.e Total coins spend: 12
The Cost of 4th bomber is: 8 i.e Total coins spend: 20
The Cost of 5th bomber is: 10 i.e Total coins spend: 30
The Cost of 6th bomber is: 12 i.e Total coins spend: 42
The Cost of 7th bomber is: 14 i.e Total coins spend: 56
The Cost of 8th bomber is: 16 i.e Total coins spend: 72
The Cost of 9th bomber is: 18 i.e Total coins spend: 90
The Cost of 10th bomber is: 20 i.e Total coins spend: 110
The Cost of 11th bomber is: 22 i.e Total coins spend: 132
The Cost of 12th bomber is: 24 i.e Total coins spend: 156
The Cost of 13th bomber is: 26 i.e Total coins spend: 182
The Cost of 14th bomber is: 28 i.e Total coins spend: 210
The Cost of 15th bomber is: 30 i.e Total coins spend: 240
The Cost of 16th bomber is: 32 i.e Total coins spend: 272
The Cost of 17th bomber is: 34 i.e Total coins spend: 306
The Cost of 18th bomber is: 36 i.e Total coins spend: 342
The Cost of 19th bomber is: 38 i.e Total coins spend: 380
The Cost of 20th bomber is: 40 i.e Total coins spend: 420
The Cost of 21st bomber is: 42 i.e Total coins spend: 462
The Cost of 22nd bomber is: 44 i.e Total coins spend: 506
The Cost of 23rd bomber is: 46 i.e Total coins spend: 552
The Cost of 24th bomber is: 48 i.e Total coins spend: 600
The Cost of 25th bomber is: 50 i.e Total coins spend: 650
The Cost of 26th bomber is: 52 i.e Total coins spend: 702
The Cost of 27th bomber is: 54 i.e Total coins spend: 756
The Cost of 28th bomber is: 56 i.e Total coins spend: 812
The Cost of 29th bomber is: 58 i.e Total coins spend: 870
The Cost of 30th bomber is: 60 i.e Total coins spend: 930
The Cost of 31st bomber is: 62 i.e Total coins spend: 992
There is a unique number which when multiplied by any number from 1 to 6, we will get the new number that contains same digits only.
Can you find that number ?
142857
142857 * 1 = 142857
142857 * 2 = 285714
142857 * 3 = 428571
142857 * 4 = 571428
142857 * 5 = 714285
142857 * 6 = 857142
These number are considered as cyclic numbers.
What will be the best approach to finding all the prime numbers less than 75 that leave an odd reminder when we divide them with 5?
Except 2 and 3, all the prime numbers are in a form of (6k +1) or (6k -1)
Therefore, you can use the formula to write down the prime numbers as:
2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 61, 67, 71, 73
Now, you can separate numbers as per the requirement that are:
3, 11, 13, 23, 31, 41, 43, 53, 61, 71 and 73
Can you solve the equation by finding the value ofA) HorseB) Cowboy bootC) Horseshoe
Horse = 10, Cowboy-Boot = 1 ,HorseShoe= 2
= Step1 =
3Horse = 30
=> Horse = 10 .....(A)
= Step2 =
1Horse + 2HorseShoe + 2HorseShoe = 18
10 + 4HorseShoe =18
HorseShoe = 2 .....(C)
= Step3 =
2HorseShoe - 2Cowboy-Boot = 2
4 - 2Cowboy-Boot = 2
=> Cowboy-Boot = 1 ... (B)
= Step4 =
Cowboy-Boot+Horse*HorseShoe = 1+10*2 =>21
You need to fill number in the bricks in the image below such that the top brick is sum of two brick below it.
It can be solved as shown below.
By using all numbers, i.e. 123456789 and subtraction/addition, operators number 100 can be formed in many ways.
Example 98 + 7 + 6 - 5 - 4 - 3 + 2 - 1 = 100
But if we add a condition that use of the number 32 is the must. Then there are limited solutions.
One of such solution is: 9 - 8 + 76 + 54 - 32 + 1 = 100
Can you tell any other solution?
9 - 8 + 7 + 65 - 4 + 32 - 1 = 100
9 - 8 + 76 + 54 - 32 + 1 = 100
Other ways of making number 100 (withiout using number 32)
98 + 7 + 6 - 5 - 4 - 3 + 2 - 1 = 100
98 - 7 - 6 - 5 - 4 + 3 + 21 = 100
9 - 8 + 76 - 5 + 4 + 3 + 21 = 100
98 - 7 + 6 + 5 + 4 - 3 - 2 - 1 = 100
98 + 7 - 6 + 5 - 4 + 3 - 2 - 1 = 100
98 + 7 - 6 + 5 - 4 - 3 + 2 + 1 = 100
98 - 7 + 6 + 5 - 4 + 3 - 2 + 1 = 100
98 - 7 + 6 - 5 + 4 + 3 + 2 - 1 = 100
98 + 7 - 6 - 5 + 4 + 3 - 2 + 1 = 100
98 - 7 - 6 + 5 + 4 + 3 + 2 + 1 = 100
9 + 8 + 76 + 5 + 4 - 3 + 2 - 1 = 100
9 + 8 + 76 + 5 - 4 + 3 + 2 + 1 = 100
A mother bought three dress for her triplets daughters(one for each) and put the dresses in the dark. One by one the girls come and pick a dress.
What is the probability that no girl will choose her own dress?
1/3
Explanation
Assuming D1 is the dress for Sister1, D2 is the dress for Sister2 and D3 is the dress for Sister3.
Therefore the total number of cases are illustrated below.
Sister1 Sister2 Sister3
D1 D2 D3
D1 D3 D2
D2 D1 D3
D2 D3 D1 ..... (1)
D3 D1 D2 .... (2)
D3 D2 D1
In both steps (1) & (2), no one gets the correct Dress.
Therefore probability that no sister gets the correct dress is 2/6 = 1/3
Can you complete below number series by replacing "?" with the correct number.
10 # 10 # 20 # ? # 110 # 300 # 930
45
Pattern goes like
10
10 * 0.5 + 5 => 10
10 * 1.0
+ 10 => 20
20 * 1.5 + 15 => 45(Ans)
45 * 2.0 + 20 => 110
110 * 2.5 + 25 => 300
300 * 3.0 + 30 => 930