#11 - The Miser Loan Puzzle

A Miser man decided to go for a vacation for a month. He goes to the bank and ask the trip loan of $500. The bank officer asks the man that the loan can only be approved when he mortgage some valuable thing at the bank. Miser man mortgages his only car whose worth was a whopping $80000. Bank officer laughed at him and approve the loan instantly. After vacation when the miser man returns, bank officer asked him "Are you an idiot, why your mortgage such an expensive car for such a short loan?".

Miser man replied with some reason and bank officer agreed that the miser man is actually not an idiot.

What did miser man replied to the bank loan officer?.

View Answer Discuss

Miser man tells the loan officer that he takes the loan to keep his expensive car safe and he also saves money on parking.

#12 - The Great Chocoberry Problem

Rohan, a 7 year old boy, was really fond of the chocolates called "Chocoberries". He asked his Mrs. Mother to give him some money to buy his favorite chocolates. His Mrs. Mother gave him Rs 45. He went to the shopkeeper and asked, "how much is one chocoberry for?". The shopkeeper said, Rs 3 for one chocolate. Also, if you give me the wrappers of three chocoberries, I will give you one for for the exchange.
In total, how many chocoberries could Rohan eat?

View Answer Discuss

22.

He can buy 15 chocolates at first from the 45 bucks that he has. Then further, he can exchange the 15 rappers to get 5 more. Then he can return 3 rappers of the 5 to get one more chocolate, and in the end use the wrapper from this one alongwith the 2 left with him to get one more. 15+5+1+1= 22.

#13 - Split Money Pizza Maths Puzzle

Rihana, Peeta, and Logan order a pizza for $10. Out of the three, Rihana and Peeta were quite hungry and ate 6 slices a piece, while Logan had just 2 slices.

Now, they want to split the cost among them fairly but due to the lack of change, they decide to round of the cost to the nearest possible dollar.

Can you find out the fair way which should be used to split the money?

What if the pizza was worth $11?

View Answer Discuss

If we assume that Rihana and Peeta pay the same amount, they can decide with "rock, paper, scissor" to determine who will pay the extra dollar. Any other method may be used as well. Suppose that Rihana pays $1 extra.

In this manner, Rihana pays $5, Peeta pays $4 and Logan pays $2.

If the pizza would have cost $11, this method will then prove to be great because both Rihana and Peeta will pay $5 each and Logan will pay $1. This will keep the offset same as previous. Rihana is paying 6% more, Peeta is paying 15% more and Logan is paying 27% more.

#14 - Logic Birthday Problem

I engaged in a strange activity. My birthday was approaching and I decided to collect money for my birthday bash. On the first day of the month, I kept a dollar in my piggy bank, on the second, I kept two dollars and on the third, I kept three and so on.

On my birthday, I had a total of 276 dollars in my piggy bank. Can you find out on which day of the month was my birthday?

Logic Birthday Problem
View Answer Discuss

23rd

The easiest way to find out without engaging in any formula would be to simply add them:
1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 + 21 + 22 + 23 = 276

Thus, the birthday falls on the 23rd day of the month.

#15 - Challenging Math Problem

You have $100 with you and you have to buy 100 balls with it. 100 is the exact figure and you cant go below or above the numbers and you have to use the entire $100. If there is no kind of tax applied how many of each of the following balls will you be able to buy:

Green Balls costing $6
Yellow Balls costing $3
Black Balls costing $0.10

Now, how many of each must you buy to fulfill the condition given?

View Answer Discuss

1 green ball = $6
29 yellow balls = $87
70 black balls = $7

Detailed Explanation :
Let us denote the number of balls to be brought with a variable
p = green sponges
q = yellow sponges
r = black sponges

Now using a simple expression:
p + q + r = 100
6p + 3q + 0.1r = 100

Multiplying the first equation by 6 then 3 and subtracting the two equations, we get:

6p + 6q + 6r = 600
3p + 3q + 3r = 300

3q = 500 - 5.9r
3p = 2.9r - 200

Usually, we have three equations to solve three variables. However, we will manage with just two here because we know that p and q are non-negative integers.
If 3q >/= 0, then 500 - 5.9r >/= 0.
Using this, r Also, if 3p >/= 0, then 2.9r - 200 > 0. This implies that r >/= 68.97.

Now, the number of black balls must be an even dollar amount or we will land up with a fraction. Considering the expressions, you know that there can be just two integers that can satisfy the condition while lying in between 68.97 and 84.75.

If we take r as 80 and solve the equations (the last two equations), we will get p = 10.67 and q = 9.33. But p and q must be integer and not fraction. Thus you can cancel out 80.

If we take r as 70, we will get p = 1 and b = 29.

Therefore following are the number of balls that we must buy:
1 green ball = $6
29 yellow balls = $87
70 black balls = $7

#16 - Hard Mathematical Logic Puzzle

A devotee visits 9 temples when he visits India. All these nine temples have one thing in common - there are 100 steps in every temple. The devotee puts Re.1 coin after climbing up every step. He does the same while climbing down every step. At each temple, the devotee offers half of his money from his pocket to god. In this way, his pocket becomes empty after his visit to 9th temple.

Can you calculate the total amount he had initially ?

Hard Mathematical Logic Puzzle
View Answer Discuss

146900

In such cases, we calculate from the last thing. Thus in this case, let us start counting from the 9th temple. Since, he must have offered 100 coins while climbing down stairs, it means that he must have offered Rs. 100 to god on the ninth temple and offered Rs. 100 while climbing up steps. Thus it is clear that he had Rs. 300 in his pocket before climbing the steps of the 9th temple.

Similarly, we will calculate for all the temples backwards.
Before eight temple: (300+100)*2 + 100 = 900
Before seventh temple: (900+100)*2 + 100 = 2100
Before Sixth temple: (2100+100)*2 + 100 = 4300
Before fifth temple: (4300+100)*2 + 100 = 8900
Before fourth temple: (8900+100)*2 + 100 = 18100
Before third temple: (18100+100)*2 + 100 = 36,500
Before second temple: (36500+100)*2 + 100 = 73300
Before first temple: (73300+100)*2 + 100 = 146900

Therefore he had Rs. 146900 initially.

#17 - Tricky Logic Problem

Sahir enters the bank he aim to rob and finds Jai standing inside armless. He aims a gun at him and asks him the code for the safe. Jai says, 'The code is different every day but if you hurt me, you will never get to know the code'.

Sahir pins him down and ties him with a rope. He then insert the code of the safe and easily takes all the money with him.

How did he know the code ?

Tricky Logic Problem
View Answer Discuss

Jai told him that the code is DIFFERENT every day. Different is the code to the safe.

#18 - Interesting Maths Puzzle

A women walks into a bank to cash out her check.
By mistake the bank teller gives her rupee amount in change, and her paise amount in rupees.
On the way home she spends 5 paise, and then suddenly she notices that she has twice the amount of her check.

How much was her check amount ?

Interesting Maths Puzzle
View Answer Discuss

The check was for Rupees 31.63.
The bank teller gave her Rupees 63.31
She spent .05, and then she had Rupees 63.26, which is twice the check.

Let x be the rupees of the check, and y be the paise.

The check was for 100x + y paise
He was given 100y + x paise

Also
100y + x - 5 = 2(100x + y)
Expanding this out and rearranging, we find:
98y = 199x + 5

or 199x ≡ -5 (mod 98)
or 98*2*x + 3x ≡ -5 (mod 98)
3x ≡ -5 ≡ 93 (mod 98)
this quickly leads to x = 31

#19 - Money puzzle

I saw a Jeans for Rs97. I dont have enough money , so i borrowed Rs50 from my mom and 50 from my dad = Rs100.
I bought the jeans, and had Rs3 change. I gave dad Rs1 and my mom Rs1 and kept the other Rs1 for myself. Now I owe my mum Rs49 and my dad Rs49. 49+49 = 98 + my Rs1 = 99. Where is the missing Rs1?

Money puzzle
View Answer Discuss

It was only a trick:
I borrowed my parents (Rs50 + Rs50 = Rs100).
I bought the jeans for Rs97 and i had Rs3 change.
So, the money that i borrowed and bought the jeans are Rs100 (borrowing money)
and the change Rs3 also the borrowing money the jeans is Rs97
Total: Rs97 + Rs3(the change) = Rs100
The money that i used to buy the jeans all i borrowed.
Rs97 is the borrowing money, change: Rs3 also the borrowing money. Rs97 + Rs3 = Rs100

#20 - Hard Short Riddles

1)How is the moon like a dollar

2)Why is the letter I like Delhi?

3)What is the shortest complete sentence in the English language

4)If you have me, you want to share me. If you share me, you haven't got me. What am I?

5)How could a cowboy ride into town on Friday, stay two days, and ride out on Friday

View Answer Discuss

1)they both have 4 quarters.
2)They both r capital of India.
3)Go.
4)Secret.
5)His horse is named Friday!