#1691 - Tricky Picture Cipher
Can you solve below picture rebus cipher ?
Ball in your court
#1692 - Driving Car Time Puzzle
Two friends hit the accelerator of their respective cars at the same time. Both of them have the same amount of petrol in their respective cars at the time they start. One can drive for 4 hours and the other can drive for 5 hours.
After driving for a while, they analyse that the amount of petrol left in one of their cars is 4 times that of the petrol left in other car.
Can you calculate how long they have been driving their respective cars ?
3.75
This question can be solved mathematically.
Let us assume that the initial amount of petrol is p.
The time for which they drove be t.
Now, the amount of petrol used by one car in t hours will be = pt / 4
The amount of petrol used by the second car in t hours will be = pt / 5
Now, the petrol left in the first car will be = (p - pt / 4)
The petrol left in the second car will be = (p - pt / 5)
According to the question
P - pt / 5 = 4(p - pt / 4)
T = 15 / 4 or 3.75 hours.
Therefore, both of the friends have driven the car for 3.75 hours.
#1693 - Find The Distance Puzzle
Two friends P and Q live near each other home. They both start driving towards each other at a constant speed. Both of them Meet 500 yards from P house. When they reach each other house, they start driving back and this time, they meet 300 yards away from Q house.
Can you find out the distance between P and Q ?
Let us assume that the distance between P house and Q house be D.
Upon their first meet, P has traveled 500 yards.
Thus the distance traveled by Q = D - 500.
Calculating D as a multiple of 100 to simplify the equation
=> Speed of P / Speed of Q = 5 / (D - 5)..... (a)
Upon their next meet, P has traveled (D - 500) + 300
Distance traveled by Q = 500 + D - 300
=> Speed of P / Speed of Q = (D - 2) / (D + 2) ..... (b)
When we equate (a) and (b)
5 / (D - 5) = (D - 2) / (D + 2)
D = 12
Therefore, the distance between P and Q house is 1200 Yards.
#1694 - Dice Probability Sum Six
Can you calculate the probability of getting a sum of six when a dice is thrown twice?
Event = {(1,5) , (2,4), (3,3), (4,2), (5,1)}
Therefore, P (getting sum = 6) = 5/36
#1696 - Send Ring Safely
Shane and Rose are madly in love with each other. To remind Rose of his pure love, Shane wants to send her a ring through post but in their country where burglary is quite prominent, any package that is not locked comes under the risk of being stolen for the contents.
Shane and Rose possesses many padlocks but neither one of them has the other key.
Can you find a way Shane can send the ring to Rose safely?
Shane can use a lockbox that can hold two locks. Shane will put the ring in the box and lock it before sending to Rose. When Rose receives the box, she can add her lock to the box and send it back to Shane.
Upon receiving the box back, Shane can simply take off his lock and send it to Rose again.
#1697 - what number comes next in the sequence
Checkout the number list below and find what number comes next in the sequence ?
111 , 113 , 117 , 119 , 123 , 137 ?
141
Its a sequence on prime number(post number 100) + 10.
7 prime number after 100 are listed below.
101 , 103 , 107 , 109 , 113 , 127 , 131
Our solution is 131+10 => 141
#1698 - World War One
Two mates Timon and Pumba were talking about their families. Timon told some nice stories concerning his unafraid grandfather who fought for the Kingdom in "World War One". Timon told that his grandparent is so brave that he was awarded a bravery medal with words "For our unafraid troopers In war One" embedded into it.
Pumba is aware of that his friend is lying. How ?
World War One was named only after World War Two
#1699 - Count Legs Puzzle
A calamity took a toll on 100 people who were brought to the same hospital. Out of the 100 patients, a few had lost their one leg. From the rest of the patients, half lost both their legs.
Can you calculate how many legs in total do the patients have now?
This is a simple problem that can be solved using average.
The average number of legs per patient who lost one leg is 1.
In the remaining patients, half people dont have a single leg and half have 2 legs. Therefore, the average leg per patient is 1 in this case as well.
Therefore, in total, the average number of legs per patient is 1.
Since there are 100 patients, the number of legs = 100.
#1700 - Correct Matchsticks Equation
Remove two matchsticks to make below statement true.
Solution is solved below.