### #1 - Tricky Math Problem

1 dollar = 100 cent

= 10 cent x 10 cent

= 1/10 dollar x 1/10 dollar

= 1/100 dollar

= 1 cent

=> 1 dollar = 1 cent

solve this tricky problem ?

step 3 is wrong

1 dollar = 100 cent

= 10 cent x 10 cent

= 1/10 dollar x 1/10 dollar

= 1/100 dollar

= 1 cent

=> 1 dollar = 1 cent

solve this tricky problem ?

step 3 is wrong

Assume you have the white pieces, can you win in a half a move ?

White should grab the rook from a1, place it at d1 and complete the castling move.

From a pack of 52 cards , i placed 4 cards on the table.

I will give you 4 clues about the cards:

Clue 1: Card on left cannot be greater than card on the right.

Clue 2: Difference between 1st card and 3rd card is 8.

Clue 3: There is no card of ace.

Clue 4: There is no face cards (queen,king,jacks).

Clue 5: Difference between 2nd card and 4th card is 7.

Identify four cards ?

2 3 10 10

The 1st card has to be 2 and last card has be 10 as there is no other way difference can be 8.

=> 2 ? 10 ?

because of clue 4, we know 4th card is 10

=> 2 ? 10 10

because of clue 5, we know 1st card is 3

=> 2 3 10 10

I saw a Jeans for Rs97. I dont have enough money , so i borrowed Rs50 from my mom and 50 from my dad = Rs100.

I bought the jeans, and had Rs3 change. I gave dad Rs1 and my mom Rs1 and kept the other Rs1 for myself. Now I owe my mum Rs49 and my dad Rs49. 49+49 = 98 + my Rs1 = 99. Where is the missing Rs1?

It was only a trick:

I borrowed my parents (Rs50 + Rs50 = Rs100).

I bought the jeans for Rs97 and i had Rs3 change.

So, the money that i borrowed and bought the jeans are Rs100 (borrowing money)

and the change Rs3 also the borrowing money the jeans is Rs97

Total: Rs97 + Rs3(the change) = Rs100

The money that i used to buy the jeans all i borrowed.

Rs97 is the borrowing money, change: Rs3 also the borrowing money. Rs97 + Rs3 = Rs100

There is a bag which have 21 blue balls and 23 red balls. You also have 22 red balls outside the bag.

Randomly remove two balls from the bag.

* If they are of different colors, put the blue one back in the bag.

* If they are the same color, take them out and put a red marble back in the bag.

Repeat this until only one marble remains in the bag.

What is the color of the sole marble left in the bag ?

The last marble will be blue.

Since balls can only be taken out in pairs and you started off with an odd number of blues there is always going to be one blue left over that you'll keep putting back in the box until it's left on it's own.

There are 3 bags and all are labeled incorrectly as follow:

Bag1 : Silver

Bag2 : Gold

Bag3 : Silver and Gold.

You need to label all bags correctly by opening just one bag.

How come ?

It have already mention that all bag have labeled in correctly

let consider

bag A-silver

bag B-gold

bag C-gold and silver

if i open bag C ..i:e gold and silver

then i should get somthing else(silver or gold) ....becouse it have already mention that all bag are labeled in correctly

so the rest 2 bag A and B should also cantain wrong item.

So.... If i assume that bag c ....cantain silver.

Then bag A(labeled silver) should cantain gold

and bag b(labeled gold)should cantain gold and silver

becouse it have mention that all bag are labeled incorrectly

A chess tournament is taking place on knock-out terms (the one who loses the match is out of the game).

(a) If 15 matches are played in total, how many players participated?

(b) If 50 players took part in the tournament, how many matches were played?

(a) If you look at the question closely, it is a knockout tournament and the winner will be just one. Thus no. of players is equal to 15+1=16.

(b) The number of matches will always be one less than the number of players (in knockout tournaments). Thus the answer is 49.

2 ladies and 2 girls need to cross a river in a boat big enough for 1 LADY or 2 girls. How do they do it?

GIRL and GIRL ->

<- GIRL

LADY ->

<- GIRL

GIRL and GIRL ->

<- GIRL

LADY ->

<- GIRL

GIRL and GIRL ->

You are an expert on paranormal activity and have been hired to locate a spirit haunting an old resort hotel. Strong signs indicate that the spirit lies behind one of four doors. The inscriptions on each door read as follows:

Door A: Its behind B or C

Door B: Its behind A or D

Door C: Its in here

Door D: Its not in here

Your psychic powers have told you three of the inscriptions are false, and one is true. Behind which door will you find the spirit?

The spirit lies behind Door D.

If the spirit is behind Door A, then both B and D are true.

If the spirit is behind Door B, then both A and D are true.

If the spirit is behind Door C, then A, C, and D are all true.

If the spirit is behind Door D, then the statements on all the doors are false, except for that on Door B. This matches the rules, and therefore, the resort hotel spirit lurks behind Door D.

3 surgeons decided to go for a camp and hired a guide for assistance. Over campfire , they met with an accident and the guide got seriously injured. The guide needs surgery(a minor one). The 3 surgeons decide to operate but they have only two medical gloves. To save the guide , all three surgeons are needed to operate on the guide, in sequence.

How can this be done without any of them being exposed to the blood of any of the others?

The first surgeon operates with the first glove (glove A) inside the second glove (glove B). The second surgeon operates using just glove B. The third surgeon operates using glove A, turned inside out, inside glove B.